2902 - Count of Sub-Multisets With Bounded Sum, saving work

2902-count-sub-multisets-with-bounded-sum.go

@@ -1,30 +1,64 @@
 package main
 
-func countSubMultisetsBrute(nums []int, l int, r int) int {
-	ln := len(nums)
-	count := 0
-	for i := 0; i < ln; i++ {
-		sum := nums[i]
-		if sum >= l && sum <= r {
-			count++
-		} else {
-			continue
-		}
-		for j := 0; j < ln; j++ {
-			if i == j {
-				continue
-			}
-			sum += nums[j]
-			if sum >= l && sum <= r {
-				count++
-			} else {
-				break
-			}
-		}
-	}
-	return count
+import (
+	"fmt"
+	"sort"
+)
+
+type NumberRange struct {
+	Start, Stop int
 }
 
-func CountSubMultisets(nums []int, l int, r int) int {
-	return countSubMultisetsBrute(nums, l, r)
+type NumberCount struct {
+	Num, Count int
+}
+
+type DistinctRange map[int]NumberRange
+
+func CountSubMultisets(nums []int, l int, r int) int {
+	numLen := len(nums)
+	if numLen == 0 {
+		return 0
+	}
+
+	if l > r {
+		return 0
+	}
+
+	sort.Ints(nums)
+	fmt.Println(nums)
+
+	if nums[0] > r {
+		return 0
+	}
+
+	if numLen*nums[numLen-1] < l {
+		return 0
+	}
+
+	ranges := make(DistinctRange)
+
+	CurrentNum := nums[0]
+	CurrentRange := NumberRange{0, 0}
+	ranges[CurrentNum] = CurrentRange
+
+	for i := 1; i < numLen; i++ {
+		if nums[i] > r {
+			numLen = i
+			break
+		}
+		r := ranges[nums[i]]
+		if CurrentNum == nums[i] {
+			r.Stop = i
+		} else {
+			CurrentNum = nums[i]
+			r = NumberRange{i, i}
+		}
+		ranges[CurrentNum] = r
+	}
+
+	fmt.Println(ranges)
+	result := 0
+
+	return result
 }