"Shortest Subarray with Sum at Least K" hard task No 862 fixed size sliding window version
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@@ -5,54 +5,32 @@ func ShortestSubarray(nums []int, k int) int {
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return -1
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return -1
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}
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}
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queue := [100000]int{}
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wndSz := 1
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queue2 := [100000]int{}
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wndStart := 0
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qIterator := &queue
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wndEnd := 0
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q2Iterator := &queue2
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wndSum := 0
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t := qIterator
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qEndPtr := -1
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qBeginPtr := -1
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q2EndPtr := -1
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q2BeginPtr := -1
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wndPrevInitialSum := 0
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lenNums := len(nums)
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lenNums := len(nums)
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for i, n := range nums {
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for wndSz = 1; wndSz <= lenNums; wndSz++ {
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if i < lenNums {
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qEndPtr++
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wndSum = wndPrevInitialSum + nums[wndSz-1]
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qIterator[qEndPtr] = n
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wndPrevInitialSum = wndSum
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}
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if wndSum >= k {
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if n >= k {
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return wndSz
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return 1
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}
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}
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}
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wndSz := 0
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for wndStart = 1; (wndStart + wndSz - 1) < lenNums; wndStart++ {
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i := 0
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for wndSz = 2; wndSz <= lenNums; wndSz++ {
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wndEnd = wndStart + wndSz - 1
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for i = wndSz - 1; i < lenNums; i++ {
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wndSum = wndSum - nums[wndStart-1] + nums[wndEnd]
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qBeginPtr++
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q2EndPtr++
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if wndSum >= k {
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q2Iterator[q2EndPtr] = qIterator[qBeginPtr] + nums[i]
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if q2Iterator[q2EndPtr] >= k {
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return wndSz
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return wndSz
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}
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}
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}
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}
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t = qIterator
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qIterator = q2Iterator
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q2Iterator = t
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qBeginPtr = q2BeginPtr
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qEndPtr = q2EndPtr
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q2BeginPtr = -1
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q2EndPtr = -1
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}
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}
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return -1
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return -1
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